Refactor interview parsing and answer splitting logic in Step4Report component

- Enhanced the `parseInterview` function to handle single-platform answers more effectively, ensuring default answers are set correctly.
- Improved the answer splitting logic to robustly identify numbered sections, accommodating various formats and ensuring cleaner output.
- Updated the handling of answer parts to remove unnecessary prefixes and trailing whitespace, enhancing overall readability.
This commit is contained in:
666ghj
2025-12-16 15:57:02 +08:00
parent 5f228357d5
commit 1659665a0b

View File

@@ -727,8 +727,16 @@ const parseInterview = (text) => {
interview.redditAnswer = redditMatch[1].trim()
}
// 如果没有明确分平台,整体作为回答
if (!twitterMatch && !redditMatch) {
// 如果只有一个平台的回答,将其作为回答
// 这样无论显示哪个平台都能有内容
if (!twitterMatch && redditMatch) {
// 只有 Reddit 回答,将其也设为 twitterAnswer 作为默认显示
interview.twitterAnswer = interview.redditAnswer
} else if (twitterMatch && !redditMatch) {
// 只有 Twitter 回答,将其也设为 redditAnswer
interview.redditAnswer = interview.twitterAnswer
} else if (!twitterMatch && !redditMatch) {
// 如果没有明确分平台,整体作为回答
interview.twitterAnswer = answerText
}
}
@@ -954,37 +962,51 @@ const InterviewDisplay = {
const splitAnswerByQuestions = (answerText, questionCount) => {
if (!answerText || questionCount <= 0) return [answerText]
// 尝试按编号分割 (如 "1." "2." 等)
// 更健壮的分割逻辑:查找所有 "数字." 格式的编号位置
// 支持格式:
// - "1. \n内容" (数字+点+空格+换行+内容)
// - "\n\n2. \n内容" (换行+数字+点+空格+换行+内容)
// 使用更宽松的匹配:开头或换行后的数字+点+空白
const numberPattern = /(?:^|[\r\n]+)(\d+)\.\s+/g
const matches = []
let match
while ((match = numberPattern.exec(answerText)) !== null) {
matches.push({
num: parseInt(match[1]),
index: match.index,
fullMatch: match[0]
})
}
// 如果没有找到编号或只找到一个,返回整体
if (matches.length <= 1) {
// 尝试移除开头的编号格式1. \n 或 1.
const cleaned = answerText.replace(/^\d+\.\s+/, '').trim()
return [cleaned || answerText]
}
// 按编号提取各部分
const parts = []
let remaining = answerText
for (let i = 1; i <= questionCount; i++) {
const nextNum = i + 1
// 查找下一个编号的位置
const nextPattern = new RegExp(`\\n\\s*${nextNum}\\.\\s+|\\n\\s*${nextNum}、|\\n\\s*${nextNum}|\\n\\s*\\(${nextNum}\\)`)
const match = remaining.match(nextPattern)
for (let i = 0; i < matches.length; i++) {
const current = matches[i]
const next = matches[i + 1]
if (match) {
// 找到下一个编号,截取当前部分
const splitIdx = match.index
let currentPart = remaining.substring(0, splitIdx).trim()
// 移除当前编号前缀
currentPart = currentPart.replace(new RegExp(`^\\s*${i}\\.\\s*|^\\s*${i}、|^\\s*${i}|^\\s*\\(${i}\\)`), '').trim()
parts.push(currentPart)
remaining = remaining.substring(splitIdx).trim()
} else if (i === questionCount) {
// 最后一个问题,取剩余所有内容
let currentPart = remaining.replace(new RegExp(`^\\s*${i}\\.\\s*|^\\s*${i}、|^\\s*${i}|^\\s*\\(${i}\\)`), '').trim()
parts.push(currentPart)
}
const startIdx = current.index + current.fullMatch.length
const endIdx = next ? next.index : answerText.length
let part = answerText.substring(startIdx, endIdx).trim()
// 移除末尾可能的多余换行
part = part.replace(/[\r\n]+$/, '').trim()
parts.push(part)
}
// 如果分割失败,返回整体答案
if (parts.length === 0 || parts.every(p => !p)) {
return [answerText]
// 如果分割成功且数量合理,返回分割结果
if (parts.length > 0 && parts.some(p => p)) {
return parts
}
return parts
return [answerText]
}
// 获取某个问题对应的回答